MATH SOLVE

4 months ago

Q:
# Given segment aed and bfc, ae=bf and ed=fc prove ad=bc What is 4???

Accepted Solution

A:

Given: [tex]\overline{AED}[/tex] and [tex]\overline{BFC}[/tex], AE = BF, and ED = FC.

We prove that AD = BC as follows:

Statement Reason

1. [tex]\overline{AED}[/tex] and [tex]\overline{BFC}[/tex] Given

2. AE + ED = AD Segment Addition Postulate

BF + FC = BC

3. AE = BF and ED = FC Given

4. BF + FC = AD Substitution

5. AD = BC Transitivity property

We prove that AD = BC as follows:

Statement Reason

1. [tex]\overline{AED}[/tex] and [tex]\overline{BFC}[/tex] Given

2. AE + ED = AD Segment Addition Postulate

BF + FC = BC

3. AE = BF and ED = FC Given

4. BF + FC = AD Substitution

5. AD = BC Transitivity property