Q:

Solve βˆ’2x2 +3x βˆ’ 9 = 0. (2 points) Select one: a. x equals quantity of 3 plus or minus 3i square root of 7 all over 4 b. x equals quantity of 3 plus or minus 9i square root of 7 all over 4 c. x equals quantity of negative 3 plus or minus 3i square root of 7 all over 4 d. x equals quantity of negative 3 plus or minus 9i square root of 7 all over 4

Accepted Solution

A:
Answer:Option A Step-by-step explanation:We have to find the solution of [tex]-2x^{2}+3x-9=0[/tex]By quadratic formula[tex]x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}[/tex][tex]=\frac{-3\pm \sqrt{(3)^{2}-4(-2)(-9)}}{2(-2)}[/tex][tex]=\frac{-3\pm \sqrt{9-72}}{-4}[/tex][tex]=\frac{3\mp \sqrt{-63}}{4}[/tex][tex]\frac{3\mp 3\sqrt{-7}}{4}=[\frac{3\mp 3i\sqrt{7}}{4}][/tex]Option A is the answer.